When the positive charge is released from the rest in the uniform electric field, what will its subsequent motion be? (You can choose more than 1 answer

In the same direction that the vector of the electric field points.

Explanation: The force of an electric field in a charge is equal to:

F = E*q

Where E is a vector here, so if q is positive, the force points in the same direction than the field and if q is negative, the force points in the opposite one.

Knowing that the charge is positive, we should expect to see the charge move in the same direction that the uniform electric field points.

This is because the force points in that direction, and by Newton's second law we have:

F = m*a

so there is an acceleration that points in the same direction that the field and this is why the charge moves in that direction.

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