Four ball are simultaneously launched with the same speed from the same height and h above the ground. At the same instant, ball 5 is released from the rest at the same height. Rank in order, from shortest to longest, the amount of time it takes each of these balls to hit the ground ( some maybe simultaneously.)

The ball 1 will take longest time to hit the ground  while ball 4 will take shortest time as per the ranking,

Ball 4 < Ball 3 <  Ball 2 = Ball 5 < Ball 1

Given data:

Four balls are simultaneously launched with the same speed from the same height and h above the ground.

And at the same instant, the ball 5 is released from the rest at the same height.

From the given picture and considering all the logical aspects, we need to consider the y component of initial velocity of each ball.  

So, the ranking will be in the order from the least to long as,

Ball 4 < Ball 3 <  Ball 2 = Ball 5 < Ball 1

Thus, we can conclude that the ball 1 will take longest time to hit the ground  while ball 4 will take shortest time as per the ranking,

Ball 4 < Ball 3 <  Ball 2 = Ball 5 < Ball 1

For more details, refer to the link below:

link

4, 3, 2 & 5, 1

Explanation:

Look at the y component of each initial velocity.  Ball 2 and 5 both have v₀ᵧ = 0, so they land at the same time.  Ball 4 has the highest downwards velocity, so it will land first.  Logically, Ball 3 will land after 4 and before 2 and 5.  Ball 1 will take the longest to land.

d

explanation:

i think the answer is d. but im not sure!