A narrow single slit (in air) in an opaque screen is illuminated by infrared light from He-Ne laser (=1152 nm). It is found that the center of the tenth dark band in the Fraunhofer pattern lies at an angle of 6.2 degree off the central axis. Determine the width of the slit. At what angle will the tenth minimum appear if the entire arrangement is immersed in water (n=1.33)?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Your answer would be false

Cvelocity of the