Physics, 04.03.2020 23:30 emmagossett2002
Imagine you derive the following expression by analyzing the physics of a particular system: a=gsinθ−μkgcosθ, where g=9.80meter/second2. Simplify the expression for a by pulling out the common factor.
a.) a = g sinθ − μk g cosθ (no simplification should be performed on the expression in this situation)
b.) a = g (sinθ−μk cosθ)
c.) a = (9.80meter/second^2)sinθ −μk (9.80 meter/second^2)cosθ
Answers: 1
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