A cylindrical conductor of length ‘l’ and area of cross section ‘A’ has a resistance ‘R’. Another conductor of length 2.5l and resistance 0.5R of the same material has area of cross section ?

R = (ρ x l)/A [Resistance = resisitivity times length divided by area of cross-section]

0.5R = (ρ x 2.5l)/A'

0.5R/2.5 = (ρ x l)/A'

R/5 = (ρ x l)/A'

R = 5(ρ x l)/A'

(ρ x l)/A = 5(ρ x l)/A'

A' = 1/5 A

A' = 0.2 A

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explanation:

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.