Suppose hydrogen and oxygen are diffusing through air. A small amount of each is released simultaneously. How much time passes before the hydrogen is 1.00 s ahead of the oxygen

Hydrogen takes 0.391s to get to distance x

Explanation:

From the chromatography table:

Using the equation. This equation relates time to distance during diffusion

,=  and ,=

Let the distance traveled be denoted by x(same distance traveled by both gases).

Distance is same when difference between and is 1.0 seconds.

At equal distance=>

=

Solving for hydrogen time:

-

=

=0.391s