A missile is moving 1350 m/s at a 25.0 degree angle. It needs to hit a target 23500 m away in a 55.0 degree direction in 10.20s. What is the direction of its final velocity?

V=

Direction is normal to the incline

Explanation:

This question tests on projectile motion.

First, calculate the acceleration of the missile.

Incline=55º,Distance=23500m, t=10seconds.

Horizontal motion of projectile

Final velocity

The vertical motion of the missile can be calculated as:

Final Velocity is:

Combining both we get

*Misile's motion is normal to the 55º incline.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

small = small current large mag large current