The image of an object formed by a lens is of magnification - 1. If the distance
between the object and its image is 60 cm, what is the focal length of the
lens? If the object is moved 20 cm towards the lens, where would the image
be formed ? State reason and also draw a ray diagram in support of your answer

answer:

Since the object is same size as that of the object therefore the object is placed at 2f and image is formed at 2f'. Therefore,

4f = 60 cm

2f = 30 cm

F = 15 cm

The magnification of -1 is possible in only convex lens. When the object is moved 20 cm towards the lens, so the new object distance will be = 30 cm - 20 cm = 10 cm. Since the new object distance is less than focal length of the lens, thus the image will be virtual, erect and magnified. The image will be formed on the same side as that of the object.

Explanation:

Look at this pic

Hope this help

Have a nice day

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

i would think it's food chain