The slit-to-screen distance is D = 200 cm , and the laser wavelength is 633 nm, use the formula for single-slit diffraction minima to find the slit width a.

Complete Question

The complete question is shown on the first uploaded image

The slit width

Explanation:

Assuming the unit on the graph is cm

Given that the slit to screen distance is D = 200 cm = 20 000 m

The wavelength  = 633 nm =

                         slit width a = ?

 The width of the spot that is the width of the peak from the graph is

            W = 1.6 × 2 = 3.2 cm

Where the 1.6 is the distance from 0 to the right  end point of the peak

        The change in y i.e has a formula

                           = Ltanθ

An the width of the spot is 2 ×

                                       W = 2Ltanθ

Applying this formula qsinθ = m

   where m = 1 because we a focused on the first zeros ,using small angle approximation we have y

Substituting this into W = 2ltanθ

         Using small angle approximation

                  W = 2ltanθ = 2Lθ

                    and this is the slit width

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

see earlier answer