A 4.9 A current is set up in a circuit for 5.4 min by a rechargeable battery with a 6.0 V emf. By how much is the chemical energy of the battery reduced?

E =9525.6 J        

Explanation:

Given that

Current ,I = 4.9 A

time ,t = 5.4 min

Voltage difference ,ΔV = 6 V

energy delivered by battery in time t is given as

E=V I t

where V is voltage, I is the current and t is the time.

now putting the values in above equation

E= 6 x 4.9 x 5.4 x 60  J   ( 1 min = 60 s , 5.4 min  = 5.4 x 60 s)

E =9525.6 J

Therefore the energy reduced will be 9525.6 J

c)as speed changes, wavelength and frequency change.

everything changes!