A tugboat tows a barge at constant speed with a 3500-kg cable. If the angle the cable makes with the horizontal where it attaches to the barge and the tugboat is 22 degrees, find the force the cable exerts on the barge in the forward direction.

6929 N is the required component of force

Explanation:

If T is the tension of the cable, the two vertical forces T sin A balance the weight.

2 T sin A = Mg

The horizontal force exerted by the barge is,

T cos A = 0.5 Mg / tan A

M = 3500 kg

g = 9.8 m/s^2, that force is:

0.5 (3500) (9.8) / (tan 22 degrees)  

= 6929 N is the required component of force

graphing motion: mastery test

209be

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time (seconds)

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i would say