Crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate

The resulting static friction force acting on the crate is 10 N.

Explanation:

Given that,

Coefficient of static friction = 0.50

Normal force = 20 N

We need to calculate the resulting static friction force acting on the crate

Using formula of static friction force

Where, N = normal force

= Coefficient of static friction

Put the value into the formula

Hence, The resulting static friction force acting on the crate is 10 N.

need to see circuit to get time constant

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