When a 4.20-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.60 cm. (a) If the 4.20-kg object is removed, how far will the spring stretch if a 1.50-kg block is hung on it

Y = 0.009 m = 0.9 cm

Explanation:

Mass m = 4.20 Kg,

Stretched spring Distance = x= 2.60 cm = 0.026 m

Weight = F= m g = 4.20 Kg × 9.81 m/s² = 41.202 N

Hook's Law F= K x

K = F/x = 41.202 N / 0.026  m

K = 1584.69 N/m

To Find the compressed spring distance Y=? when 1.5 kg block still hung on it So F = mg = 1.5 x 9.81 = 14.715 N

Y = F/k =  14.715 N / 1584.69 N/m

Y = 0.009 m = 0.9 cm

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!