A 10-cm-diameter circular loop of wire is placed in a 0.84-T magnetic field. Part A When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?

When the plane of the loop is perpendicular to the field lines, the magnetic flux through the loop is  6.284 x 10⁻³ wb.

Explanation:

The magnetic flux through the loop is the product of magnetic field strength, circular area of the loop and angle of inclination.

Ф = BAcosθ

When the plane of the loop is perpendicular to the field lines, θ = 0

Ф = BAcos0

Ф = BA

Where;

Ф is the magnetic flux through the loop

B is the magnetic field strength = 0.8 T

A is the circular area of the loop;

Ф = 0.8 x 0.007855 = 6.284 x 10⁻³ wb

Therefore, when the plane of the loop is perpendicular to the field lines, the magnetic flux through the loop is  6.284 x 10⁻³ wb.

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm