A silver wire 2.6 mm in diameter transfers a charge of 420C in 80 minutes. Silvercontains 5.8 x 10 28 electrons per cubic meter. a) What is the current in the wire?b) What is the magnitude of the drift velocity of the electrons in the wire?

a)

b)

And solving for vd we got:

We know that and replacing we have:

And replacing we got:

Explanation:

For this case we have the following data given:

[tex[ d = 2.6 mm= 0.0026 m[/tex] represent the diameter

represent the radius

represent the charge

represent the time

Part a

For this case we want to find the current flow I, and by definition we know that :

And replacing we have:

Part b

For this case we want to find the velocity associated to the drift velocity, and for this case we can use the following formula:

And solving for vd we got:

We know that and replacing we have:

And replacing we got:

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )