You collect hydrogen gas over water at 323 K. The partial pressure of hydrogen is 122.4, and the total pressure is 134.7 kPa. What is the pressure of the water vapor

12.3kPa

Explanation:

Using Dalton's law which states: in a mixture of gases the total pressure is equal to the  sum of the pressures of all gases present.  In this question,

Total Pressure = Pressure of Hydrogen + Pressure of water vapor

Pressure of Hydrogen = 122.4kPa

Total Pressure  134.7kPa.

Pressure of water vapor = Total pressure - Pressure of Hydrogen =

134.7kPa - 122.4kPa = 12.3kPa.  

Vapor pressure of water at certain temperatures is is usually available in vapor pressure table.  In this question temperature here is 323 K.  

Convert 323 K to celsius (using the formula Celsius = K -273) will give us 323 k -273 = 50 degrees celsius.  Checking the vapor pressure of water at 50 degrees celsius will show you 12.34kPa

12.3 kPa ^^^

Explanation:

I took the test, just confirmation that the above answer is correct ;-)

i was thinking more like reflects green light, just not sure

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft