After the box comes to rest at position x1, a person starts pushing the box, giving it a speed v1. When the box reaches position x2 (where x2>x1), how much work Wp has the person done on the box

0.5m(v1)²

Explanation:

We know that work done on an object is equal to the change in the kinetic energy of that object. Hence,

W. D = ΔK. E.

ΔK. E. = K. E.(final) - K. E.(initial)

Initial Kinetic energy, K. E.(initial), is:

K. E.(initial) = 0 (the box was at West)

Final K. E., K. E.(final) is:

K. E.(final) = 0.5*m*(v1)²

Hence, work done on the box will be:

W. D. = 0.5m(v1)² - 0

W. D. = 0.5m(v1)²

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

connect the batteries in series and hope