A load of 36 N attached to a spring hanging
vertically stretches the spring 6.5 cm. The
spring is now placed horizontally on a table
and stretched 10 cm.
What force is required to stretch it by this
amount?
Answer in units of N.

115.38N

Explanation:

Firstly, let's determine the constant.

Hooke's law was discovered by Robert Hooke in 1660.

Using hooke's law which states that provided the elastic limit of an elastic material is not exceeded, the force is equal to the extension applied provided all factors are kept constant.

Hooke's Law is a principle of physics that states that the force which is needed to extend or compress a spring by some distance is proportional to that distance

Therefore,

Force=kx

K= F/x

Where Force= 75m

x= 0.065m

K= 75/0.065m

K= 1153. 846N

We can use the constant to find the force when the distance that is stretched(x) is known.

Here

Force=kx

F= 1153.846 × 0.10

F= 115.38N

The force required to stretch it by this amount is 115.38N.

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