What is the minimum area of the top surface of a slab of ice with a uniform thickness of 0.30 m floating on fresh water that will hold up a car of mass 1100 kg sitting at the center on the top surface? The density of water is 1.0 × 103 kg/m3 and density of ice is 0.92 × 103 kg/m3 .

The minimum area of the top surface of a slab of ice is 45.8 m²

Explanation:

Given that,

Thickness = 0.30 m

Mass of car = 1100 kg

Density of water

Density of ice

We need to calculate the minimum area of the top surface of a slab of ice

Using Buoyant force force

Total weight of car + ice weight = weight of water displaced

Put the value into the formula

Hence, The minimum area of the top surface of a slab of ice is 45.8 m²

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.