A satellite of mass =238 kg is in circular orbit around the Earth at an altitude above the earth's surface equal to the earth's mean radius (6370 km). At this distance, the free-fall acceleration is /4.What are (a) the speed and (b) the magnitude of the centripetal acceleration of the satellite?

Explanation:

a) the speed=

V=√2gr²/2r

=√gr/2

√10*637/2

V=31850m/s²

Magnitude of the acceleration

a=Gm/r²

10*238/(6370)²

2380/12740

=0.187

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.