How to find normal force when given coefficient of force and frictional force?

Explanation:

F =ų × R

Where

F is the frictional force

R is the normal reactional force

Ų is the coefficient of force.

Make R the subject of the formula

R = F/Ų

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

i think they are all correct

explanation:

they seem good