In performing the Grignard reaction under the conditions of Experiment 16, if you were to use 121 mg of benzophenone (182.21 g/mol), 18 mg of magnesium (24.30 g/mol), and 76 microliters of bromobenzene (157.02 g/mol, 1.50 g/mL), calculate the theoretical yield of triphenylmethanol (260.33 g/mol), in mg. Benzophenone is the limiting reactant. Enter your answer as digits only, no units, using the proper number of significant figures.

The theoretical yield of triphenylmethanol is 0.173 grams

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of benzophenone = 121 mg = 0.121 g   (Conversion factor:  1 g = 1000 mg)

Molar mass of benzophenone = 182.21 g/mol

Putting values in equation 1, we get:

The chemical equation for the formation of triphenylmethanol from benzophenone follows:

As, bromobenzene is the limiting reagent. So, it will limit the formation of products

By Stoichiometry of the reaction:

1 mole of bromobenzene produces 1 mole of triphenylmethanol

So, of bromobenzene will produce = moles of triphenylmethanol

Now, calculating the mass of triphenylmethanol from equation 1, we get:

Molar mass of triphenylmethanol = 260.33 g/mol

Moles of triphenylmethanol = moles

Putting values in equation 1, we get:

Hence, the theoretical yield of triphenylmethanol is 0.173 grams

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