An infinite cylinder of radius R has a linear charge density λ. The volume charge density (C/m3) within the cylinder (r≤R) is rho(r)=rho0rR, where rho0 is a constant to be determined.

ρ₀ = 3λ/(2πR⁴)

Explanation:

If we take an elemental part of the cross sectional Area of the infinitely long cylinder.

The small elemental part has a small length dr in the cylinder's radial direction such that the cross sectional Area of the elemental part = 2πr dr

The linear density over the entire radial length of the cylinder will be equal to the sum of (volume charge density × elemental cross sectional Area)

That is,

λ = Σ ρ₀rR × 2πr dr

summing from 0 to R

λ = ∫ᴿ₀ (ρ₀rR × 2πr) dr

λ = ∫ᴿ₀ ρ₀R × 2πr² dr

λ = [ρ₀R × 2πr³/3 ]ᴿ₀

λ = (2π ρ₀R/3) [ r³ ]ᴿ₀

λ = (2π ρ₀R/3) [ R³ ]

λ = 2π ρ₀R⁴/3

ρ₀ = 3λ/(2πR⁴)

with 5 seconds, no, but over time if the police car stays at 65m/s ad the speeding car stays at 60, then obviously yes, but the answer to your question would be, no.

hope this : )

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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