During a race the dirt bike was observed to leap up off the small hill at A at an angle of 60^o with the horizontal. If the point of landing is 20 ft away, determine the approximate speed at which the bike was traveling just before it left the ground. Neglect the size of the bike for the calculation.

Velocity is equal to feet per second  and time is equal to seconds

Explanation:

Given

The horizontal distance traveled by  dirt bike before landing feet

Angle of flight degree

As we know that Horizontal distance (H) is equal to

Where is the initial horizontal distance

is the velocity with which the bike is travelling in horizontal direction

and is the time in seconds

Substituting the given values, we get -

Now distance traveled in vertical direction is equal to

here acceleration will be equal to acceleration due to gravity which is equal to . It is negative as its is acting in upward direction

Thus,

Velocity is equal to feet per second  and time is equal to seconds

f=ma newton's second law 7x8=56n

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.