In a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times free-fall acceleration. What is the radius of the turn if the falcon is flying at 22 m/s?

32.925 m.

Explanation:

The formula of  centripetal acceleration is

a = v²/r Equation 1

Where a = centripetal acceleration, v = linear velocity, r = radius.

make r the subject of the equation.

r = a/v² Equation 2

Given: v = 22 m/s,

a = 1.5 times free fall acceleration

Note: Free fall = 9.8 m/s²

Therefore, a = 1.5×9.8 = 14.7 m/s²

Substitute into equation 2

r = 22²/14.7

r = 484/14.7

r = 32.925 m.

Hence the radius of the turn = 32.925 m.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000