Physics, 28.09.2019 02:30 Blazingangelkl

Calculate the amount of energy produced by the conversion of 50.0 kg of mass into energy. use 3.00 x 108 m/s for the speed of light. which setup will solve this problem? e = (50.0 kg)(3.00 x 108 m/s) e = (50.0 kg)(3.00 x 108 m/s)2 e = (50.0 kg)(3.00)(1 x 108 m/s)2 the amount of energy released when 50.0 kg is converted into energy is x 10a.

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Answer from: chanahvanya

Option (b) is the correct answer.

Explanation:

According to Albert Einstein, mass energy equivalence states that any object or substance which has mass will also have an equivalent amount of energy.

Mathematically, the relation is as follows.

$E = mc^{2}$

where, E = energy

m = mass

c = speed of light

It is given that mass is 50.0 kg and speed of light is $3 \times 10^{8} m/s$ . Therefore, calculate the energy as follows.

$E = mc^{2}$

= $50.0 kg \times (3 \times 10^{8}m/s)^{2}$

= $45 \times 10^{9} kg m^{2}/s^{2}$

Thus, we can conclude that the amount of energy released when 50.0 kg is converted into energy is $45 \times 10^{9} kg m^{2}/s^{2}$ .

Answer from: brandon1888

Explanation :

In this case, we have to find the amount of energy produced by the conversion of 50 kg mass into energy.

We know that mass can be converted to energy by using Einstein mass energy equivalence equation.

Mathematically, it can be written as :

E=mc^2

Where,

m is the mass

and c is the speed of light

So, $E=(50\ kg)(3\times 10^8\ m/s)^2$

$E=4.5\times 10^{18}$

Hence, the correct option is (B).

The amount of energy released when 50.0 kg is converted into energy is $E=4.5\times 10^{18}$

Answer from: Quest

with 5 seconds, no, but over time if the police car stays at 65m/s ad the speeding car stays at 60, then obviously yes, but the answer to your question would be, no.

hope this : )

Answer from: Quest

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm. the wire diameter is d = 0.9 mm. the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2) in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

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