Eight joules of work is required to stretch a spring 0.5 meter from its natural length. Find the work required to stretch the spring an additional 0.40 meter.

Additional Work done to stretch the spring 0.4m is 6.4J

Explanation:

Given -

Work done to stretch a spring, W1 = 8J

Distance , d = 0.5m

Distance2, x = 0.4m

Work done 2, W2 = ?

Using Hooke's law,

Work done = k x

where k is spring constant

For distance 0.5m :

8 J = k X 0.5m

k = 8/0.5 = 16 J/m

For distance 0.4m:

W2 = 16 X 0.4 J

W2 = 6.4J

Additional Work done to stretch the spring 0.4m is 6.4J

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: