Two blocks are in contact on a frictionless, horizontal tabletop. An external force, F ,is applied to block 1, and the two blocks are moving with a constant acceleration of 2.70 m/s2. Use M1 = 3.03 kg and M2 = 6.40 kg. (a) What is the magnitude, F, of the applied force? (b) What is the contact force between the blocks? (c) What is the net force acting on block 1? {25.5 N, 17.3 N, 8.18 N to the right}

Explanation:

The blocks are moving in the x direction

Given that,

m1=3.03kg

m2=6.40kg

After a force F is applied to the two masses they move with an acceleration of 2.7m/s²

Newton's Second Law:

ΣF = Σ(ma) = m1a1 + m2a2

Therefore

But in this case a1 =a2=2.7m/s², because they are connected by a string and they are accelerating at the same speed.

F=(m1+m2)a

F=(3.03+6.40)2.7

F=9.43 ×2.7

F=25.46N.

b. The contact force be blocks

F2= m2a

F2 is the force between the blocks

F2=6.4×2.7

F2= 17.28N

c. Fnet on block 1

It is the net force pulling the two blocks forward minus the force between the block 1 and 2

F1=F-F2

F=25.46-17.28

F=8.18N

The net force on block 1 is 8.18N

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: