When the driver first notices the garbage can, the distance between the car and the can is x2−x0=d. You have found that the distance traveled by the car before the brakes are applied is v0t. Find the distance x2−x1 traveled by the car after the brakes are applied.

The distance travelled when the brakes are applied, (x2 - x1) = (d - v₀t)

Acceleration of the car after brakes are applied = - [v₀²/(d - v₀t)]

Explanation:

The driver initially distance d, away from the can, travels a further distance of v₀t.

New distance of the driver from the can = (d - v₀t)

And it is said that the driver stops just before the can,

Hence, the distance travelled when the brakes are applied, x2 - x1 = (d - v₀t)

The acceleration after the application if the brakes is obtained from the equations of motion.

Distance travelled = (d - v₀t)

Initial velocity before the application of brakes = v₀ m/s

Final velocity = 0 m/s

acceleration = ?

√ ²

But we know acceleration is negative, since it is deceleration.

Using v₀² = 0 - 2a(d - v₀t)

a =- [v₀²/(d - v₀t)]

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia