A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30° angle. The block’s initial speed is 10 m/s. What vertical height does the block reach above its starting point? What speed does it have when it slides back down to its starting point?

Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s

Explanation:

Given Data:

V is the overall velocity vector, and are its initial vertical and horizontal components

To find:

Max Height achieved

Calculation:

1) Using the equation of motion, we know

2) In terms of gravity height and  the vertical component of Velocity .

3) As as at maximum height the vertical component of velocity is zero maximum height achieved

putting values

4)

5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)

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