Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 12,900 kg. The thrust of its engines is 27,500 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.)

(a) Calculate its magnitude of acceleration in a vertical takeoff from the Moon. m/s2

(b) Could it lift off from Earth? If not, why not? (CHOOSE ONE OF THE OPTIONS)

-Yes, the thrust of the module's engines is greater than its weight on Earth.

-No, the thrust of the module's engines is less than its weight on Earth.

-No, the thrust of the module's engines is equal to its weight on Earth.

-Yes, the thrust of the module's engines is equal to its weight on Earth.

If it could, calculate the magnitude of its acceleration. (If not, enter NONE.) m/s2

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

They all deal with hard evidence(scientific)

M= 700 kgvalue of g( gravity) is constant = 9.8 m/s² or 10 m/s² w = mg = 700*9.8 = 6860n or 6.680*10³ n