The rate constant for the reaction is 0.230 M − 1 ⋅ s − 1 0.230 M−1⋅s−1 at 200 ∘ C. 200 ∘C. A ⟶ products A⟶products If the initial concentration of A A is 0.00290 M, 0.00290 M, what will be the concentration after 155 s?

The concentration after 155 s = 0.00263 M

Explanation:

From the units of the reactions rate constant, K = 0.230 M⁻¹s⁻¹, it is evident that the reaction is second order with respect to the reactant A.

Let C = concentration of A At any time

And C₀ = initial concentration of A = 0.00290 M

dC/dt = - KC²

dC/C² = - kdt

C⁻² dC = - k dt

∫ C⁻² dC = -k ∫ dt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

- (C⁻¹ - C₀⁻¹) = - kt

(C⁻¹ - C₀⁻¹) = kt

(1/C) - (1/C₀) = kt

t = 155 s, C₀ = 0.00290 M, k = 0.230 M⁻¹s⁻¹

(1/C) - (1/0.0029) = 0.23 × 155

(1/C) = 35.65 + 344.83 = 380.478

C = 1/380.478 = 0.00263 M

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.