Physics, 25.02.2020 22:26 redrosesxx
A parallel plate capacitor is charged to a potential difference of 100 V and disconnected from the source. A slab of dielectric is then inserted between the plates. (a) Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is introduced to the energy stored in the empty capacitor is U/U0 = k.
(b) Give a physical explanation for this increase in stored energy.
(c) What happens to the charge on the capacitor? Note: This situation is not the same as when the battery is removed from the circuit before the dielectric is introduced.
Answers: 3
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A parallel plate capacitor is charged to a potential difference of 100 V and disconnected from the s...
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