2.00 × 10 − 3 mol of potassium ions pass through a cell membrane in 4.00 × 10 − 2 s. (a) Calculate the electric current and (b) describe its direction relative to the motion of the potassium ions

Explanation:

(a)  The given data is as follows.

          Number of moles of potassium = 0.002 mol

          time =

First, we will calculate the number of ions as follows.

          No. of ions =

                             = 0.012 mol

Charge will be calculated as follows.

   q =

       =

Hence, we will calculate the current as follows.

               Current =

                             =

                             = 4750 Ampere

Thus, we can conclude that electric current 4750 ampere.

(b)  As we know that current is the flow of electrons or ions. Therefore, the direction in which potassium ions will flow will also be the direction of electric current.

where are the vectors ?