A particle moves with acceleration a(t) m/s^2 along an s-axis and has velocity vo m/s at time t=0. find the displacement and the distance traveled by the particle during the time interval

The displacement and distance is 22 m and 20.09 m.

Explanation:

Suppose, a(t)=11

v₀=-1 ; 0<t<2.....these are meant to be less than or equal to symbols

Given that,

Acceleration = 11 m/s²

We need to calculate the displacement

Using equation of velocity

On integration

Put the value of v₀

The displacement is 22 m.

We need to calculate the distance

Using formula of distance

Hence, The displacement and distance is 22 m and 20.09 m.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

answera compound;