To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.7 m.

Incomplete question.The complete question is here

To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.7 m.If the thrower takes 1.0 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

Explanation:

Radius r=1.7m/2 =0.85 m

The angular displacement in time t is:

θ=1/2αt²

where α is angular acceleration

Given

θ=2π

t=1.0s

So

α=2θ/t²

Angular speed after 1.0s is:

Speed of discus is given by:

the answer is b

explanation:

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force