An electron is acted on by two electric forces, one of 2.7×10-14 N acting upward and a second of 5.8×10-14 N acting to the right. What is the magnitude of the electric field at the electron’s location?

3.99×10⁵ N/C

Explanation:

Assuming both force forms a right angle triangle,

Using Pythagoras theorem,

a² = b²+c² Equation 1

Where a= resultant of the two forces, b = the force acting upward, c = the force acting to the right.

make a the subject of the equation.

a = √(b²+c²) Equation 2

Given: b = 2.7×10⁻¹⁴ N, c = 5.8×10⁻¹⁴ N.

Substitute into equation 2

a = √[(2.7×10⁻¹⁴)²+( 5.8×10⁻¹⁴ )²]

a = √[7.28×10⁻²⁸)+(33.64×10⁻²⁸)]

a = √(40.92×10⁻²⁸)

a = 6.397×10⁻¹⁴ N.

But,

F = Eq Equation 3

Where E = Electric Field, q = charge of an electron, F = electric force.

make E the subject of the equation,

E = F/q Equation 4

Given: F = 6.397×10⁻¹⁴ N, q = 1.602×10⁻¹⁹  C.

Substitute into equation 4

E =  6.397×10⁻¹⁴/(1.602×10⁻¹⁹ )

E = 3.99×10⁵ N/C

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

does anyone know or what?