Light of wavelength 500 nm falls normally on 50 slits that are 2.5×10−3mm wide and spaced 5.0×10−3mm apart. How many interference fringes lie in the central peak of the diffraction pattern?

3

Explanation:

The solution is in the attached files below

The answer is a) taiga because taigas are cold

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current