An 8.0-g bullet with a speed of 800 m/s is shot into a wooden block and penetrates 20 cm before stopping. What is the average force of the wood on the bullet? Assume the block does not move

The answer to your question is F = 16 N

Explanation:

Data

mass = 8 g

vo = 800 m/s

distance = 20 cm

force = ?

vf = 0 m/s

Process

1.- Calculate the acceleration of the bullet

Formula

  a = (vf² - vo²)/2d

Substitution

  a = (0 - 800)/2(0.2)

  a = -800/0.4

  a = 2000 m/s²

2.- Convert 8g to kg

           1000 g   1 kg

                 8 g   x

             x = (8 x 1)/1000

             x = 0.008 kg

3.- Calculate the force

Formula

      F = ma

Substitution

      F = (0.008)(2000)

Simplification and result

      F = 16 N

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle