If a second resistor with R2 = 19.0 Ω is connected in series with R1, what is the total rate at which electrical energy is dissipated by the two resistors?

Total rate at which electrical energy is dissipated by the two resistors are V²/R  or I²R.

Explanation:

When the two resistors are combined in series then the total resistance gets added.

If and are in series then total resistance, R =

Total resistance becomes + 19 Ω

The total electrical power dissipated is equivalent to the power dissipated.

We know,

Power = V²/R  or

Power = I²R

where, V is the potential difference between the ends

            I is the current supplied.

Therefore, total speed at which electrical power is consumed by the two resistors are V²/R  or I²R.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

where’s the list ? the question is incomplete