Physics, 22.02.2020 11:42 janahiac09

A 12.0 V battery is connected to two resistors in series:
R1 = 12.00 , R2 = 4.00 .

Answers: 3

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Answers

The Req is 16 ohm, total current is same for both i.e. 0.75A and voltage are 9V and 3V for resistor R1 and R2 respectively.

Explanation:

For series combination, resistance are added, Req = R1 + R2 = 16 ohm.

V(total)= I(total) * Req

or, I(total)=V/Req=12/16=0.75 amp.

Now,

Voltage across R1= I(total) * R1= 0.75* 12=9V

Voltage across R2= I(total) * R2= 0.75* 4=3V

However, in parallel combination, voltage is constant across both the resistance, current is different in both the resistance and total resistance is calculated by the following expression:R(parallel) = (R1 * R2)/ R1+R2

Answer from: Quest

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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A 12.0 V battery is connected to two resistors in series:
R1 = 12.00 , R2 = 4.00 ....

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