A helicopter accelerates vertically from the ground from rest at 2 m/s2. 3 s after the helicopter leaves the ground a mailbag is dropped from the helicopter. What is the speed of the mailbag just before it hits the ground? (The helicopter is moving when the bag is dropped.)

The velocity of the mailbag just before it hits the ground is 14.57 m/s.

Explanation:

Given that,

Acceleration = 2 m/s

Time = 3 sec

We need to calculate the velocity of mailbag

Using equation of motion

Put the value into the formula

We need to calculate the height at which the mailbag dropped

Using equation of motion

Put the value into the formula

We need to calculate the velocity of the mailbag just before it hits the ground

Using equation of motion

Put the value into the formula

Hence, The velocity of the mailbag just before it hits the ground is 14.57 m/s.

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