In a baseball game, a batter hits the 0.150-kg ball straight back at the pitcher at 180 km/h .

If the ball is traveling at 160 km/h just before it reaches the bat, what is the magnitude of the average force exerted by the bat on it if the collision lasts 5.0 ms ?

F = ?

F = 0.17N

Explanation: From the Newton second law of motion.

F= m(v-u)/t.

V=180km/hr = 180×1000/3600= 50m/s

U= 160km/hr = 160×1000/3600= 44.44m/s

t= 5secs

F=m(v-u)/t

F= 0.150(50-44.44)/5

F=0.150×5.56/5

F= 0.835/5

F= 0.17N rounded to two decimal places.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid