The diffusion coefficients for silver in copper are given at two temperatures: VMSE: D0 and Qd from Experimental Data T (°C) D (m2/s) 650 5.5 × 10−16 900 1.3 × 10−13 (a) Determine the values of D0 and Qd. (b) What is the magnitude of D at 875°C?

Explanation:

From the formula;

When T = 923 K and D = 5.5 x 10-16 m2/s

923 x R = Qd / [lnDo - ln(5.5 x 10-16 m2/s)] (1)

When T = 1173 K and D = 1.3 x 10-13 m2/s

Plugging the values ; and dividing equation 1 by 2

1173 x R = Qd / [lnDo - ln(1.3 x 10-13 m2/s)] (2)

b) T = 875°C = 875+273 = 1148K

Hence 1148 x 8.314 JK-1mol-1 = 196783.83 J / [ln(7.54x10-5 m2/s) - lnD]

D = 8.38x10-14 m2/s

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow