It takes 3.0 μJ of work to move a 17 nC charge from point A to B. It takes -6.5 μJ of work to move the charge from C to B. Part A What is the potential difference VC−VA? Express your answer using two significant figures.

Explanation:

Charge move from A to B

Work to move from A to B = 3 μJ

Work to move from C to B = - 6.5 μJ

charge, q = 17 nC = 17 x 10^-9 C

VB - VA = q x work from A to B

VB - VA = 17 x 10^-9 x 3 x 10^-6

VB - VA = 51 x 10^-15 J     (1)

VC - VB = q x work from C to B

VC - VB = - 17 x 10^-9 x 6.5 x 10^-6

VC - VB = - 110.5 x 10^-15 J    ... (2)

Add equation (1) and (22), we get

VC - VA = VC - VB + VB - VA

VC - VA = -110.5 x 10^-15 + 51 x 10^-15

VC - VA = - 59.5 x 10^-15 V

The potential difference VC−VA is 533.33 V

Explanation:

please look at the solution in the attached Word file

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

neither accurate nor precise.