An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucleus of lead (charge +82e=+1.31×10−17C+82e=+1.31×10−17C) . You may treat both objects as point charges. How much work would you have to do to move the electron to a distance 5.00×10−10m5.00×10−10m from the center of the lead nucleus

Explanation:

According to Coulomb's law, the force of attraction between two point charges, and , separated by a distance is given by

is a constant with a value of .

When we substitute the values from the question,

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

This is negative because work is done on the electron, not by it.

there are no contact forces mentioned on the list of choices that you've provided.