A machine in an ice factory is capable of exerting 3.00x10^2 N of force to pull a large block of ice up a slope. The block weighs 1.22 x 10^4 N. Assuming there is no friction, what is the maximum angle that the slop can make with the horizontal if the machine is able to complete the task?

14.24°

Explanation:

Force applied to the object up the plane is the moving force (Fm). The frictional force (Ff) is always acting up the plane. Since there is no friction, frictional force is 0N. Therefore the only force needed to move the body up the slope is the moving force. Mathematically,

Fm = Wsin(theta) {force acting along the plane}

Given Fm = 300N, Weight = 1220N

Substituting this values in the formula to get theta we have;

300 = 1220sin(theta)

sintheta = 300/1220

Sintheta = 0.246

theta = arcsin 0.246

theta = 14.24°

Therefore, the maximum angle that the slop can make with the horizontal if the machine is able to complete the task is 14.24°

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right