A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest at an initial displacement of 0.296 mm . A damping force Fx=−bvxFx=−bvx acts on the egg, and the amplitude of the motion decreases to 0.120 mm in a time of 4.55 ss .

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g=

Constant force=F=25.6 N/m

Initial displacement=

Final displacement=

Time=t=4.55 s

Damping force=

We have to find the  magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

For maximum displacement

Therefore ,

Substitute the values

Substitute the values

Hence,the  magnitude of damping constant b=0.022kg/s

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015