Now let’s examine the case of a ball being thrown vertically upward. Even though the ball is initially moving upward, it is, nevertheless, in free fall and we can use the following equations to analyze its motion. vyyv2y===v0y−gty0+v0yt−12gt2v20y−2g (y−y0) Suppose you throw a ball vertically upward from the flat roof of a tall building. The ball leaves your hand at a point even with the roof railing, with an upward velocity of 15.0 m/s. On its way back down, it just misses the railing. Find (a) the position and velocity of the ball 1.00 s and 4.00 s after it leaves your hand; (b) the velocity of the ball when it is 5.00 m above the railing; and (c) the maximum height reached and the time at which it is reached. Ignore the effects of the air.