Two flat conductors are placed with their inner faces separated by 8 mm. If the surface charge density on one of the inner faces is 33 pC/m2 and the other inner face −33 pC/m2, what is the magnitude of the electric potential difference between the two conductors? Answer in units of V

= 0.0298V

Explanation:

Electric field between two conductor = σ / ε₀

σ = 33pC/m²

= 33 × 10⁻¹²C/m²

ε₀ = 8.85 × 10 ⁻¹²C²/Nm²

E = 33 × 10⁻¹² /  8.85 × 10 ⁻¹²

  = 3.7288N/C

potential difference between two conductors = Ed

where d = 8mm = 8 × 10 ⁻³m

V = 3.7288 ×  8 × 10 ⁻³

   = 29.83 × 10 ⁻³

    = 0.0298V

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down